/*异或的简单应用 a^a = 0*/class Solution {public: int singleNumber(int A[], int n) { int sum = 0; for(int i = 0 ; i < n ; i++){ sum = sum^A[i]; } return sum; }};
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/*异或的简单应用 a^a = 0*/class Solution {public: int singleNumber(int A[], int n) { int sum = 0; for(int i = 0 ; i < n ; i++){ sum = sum^A[i]; } return sum; }};
转载于:https://www.cnblogs.com/llei1573/p/4374784.html